Davin News Server

On 2025-10-21, AlleyCat <katt@gmail.com> wrote:
>
> On Mon, 20 Oct 2025 08:54:49 +0200,  -hh says...  
>
>> Having a 'direct line of sight" doesn't make it a meaningful threat.
>
> You fucking moron... it's DEER stand. If hunters don't have "line of sight" 
> from a deer stand, why build the fucking thing where they don't?
>
> My god, man... are you that stupid, or just trying to get us to think you are?
>
>> Case in point, we also have a direct line of sight to the moon, and it is
>> well out of anyone's firing range.
>
> That is THE stupidest thing ANYONE has EVER said here.

I had to read it several times just to see if I missed something ie:sarcasm.
I didn't.


> God DAMN me, for thinking you were one of the smart ones.


At first I thought it was one of Rudy's forgeries.
It isn't.


> More reductio ad absurdum:
>
> Maybe Trump should have Air Force One park on the moon? 
>
> Maybe the assassin could rent a rocket from Elon Musk and fly into orbit, if 
> he did, making your stupid fucking analogy moot.
>
> In outer space, there is no air resistance to slow down a bullet, so it would 
> travel much farther than it would on Earth. The distance a bullet travels in 
> space depends on its initial velocity and the lack of external forces acting 
> upon it.
>
> The muzzle velocity of a .30 caliber bullet can vary depending on the specific 
> cartridge and rifle used, but a typical muzzle velocity for a .30-06 
> Springfield rifle is around 2,700 feet per second (823 meters per second).
>
> In the vacuum of space, the bullet would maintain its initial velocity almost 
> indefinitely, as there is no air resistance to slow it down. However, it would 
> still be subject to the effects of gravity from nearby celestial bodies.
>
> Assuming the bullet is fired in a direction perpendicular to the Earth's 
> gravity, and neglecting the effects of gravity from other celestial bodies, we 
> can estimate the distance the bullet would travel.
>
> The kinetic energy of the bullet is given by KE=21mv2, where m is the mass of 
> the bullet and v is its velocity. For a .30-06 bullet, the mass is 
> approximately 0.18 kg (6.2 oz) and the velocity is 823 m/s.
>
> However, to estimate the distance traveled in space, we consider that the 
> bullet will travel in a straight line until it encounters another 
> gravitational field or an external force.
>
> Given that we do not know the direction of the bullet or the frame of 
> reference, let's assume it travels at a constant velocity of 823 m/s.
>
> The maximum distance the bullet could travel in a given time t would be d=v·t.
>
> Without a specified time, we can consider that in one year (approximately 3.15
> ×107 seconds), the bullet would travel about d=823·3.15×107?2.59×1010 meters 
> or about 25.9 million kilometers.
>
> To put that in perspective, the Moon is about 384,400 kilometers away from 
> Earth, so the bullet could reach the Moon in about 468 seconds or 
> approximately 7.8 minutes.
>
> Keep in mind that this calculation assumes a constant velocity and neglects 
> any gravitational influences. In reality, the bullet's trajectory would be 
> influenced by the gravitational fields of nearby celestial bodies, causing its 
> path to curve over long distances.
"

Thanks for the physics lesson Professor AlleyCat.

:) 


-- 
pothead
"I have a lot of friends who are Democrats, and they’re idiots.
I always say they have big hearts and little brains.
Almost every single policy rolled out failed.”

-- Jamie Dimon CEO JPMorgan Chase.