Davin News Server

On 2025-10-21 06:05, pothead wrote:
> On 2025-10-21, AlleyCat <katt@gmail.com> wrote:
>>
>> On Mon, 20 Oct 2025 08:54:49 +0200,  -hh says...
>>
>>> Having a 'direct line of sight" doesn't make it a meaningful threat.
>>
>> You fucking moron... it's DEER stand. If hunters don't have "line of sight"
>> from a deer stand, why build the fucking thing where they don't?
>>
>> My god, man... are you that stupid, or just trying to get us to think you are?
>>
>>> Case in point, we also have a direct line of sight to the moon, and it is
>>> well out of anyone's firing range.
>>
>> That is THE stupidest thing ANYONE has EVER said here.
> 
> I had to read it several times just to see if I missed something ie:sarcasm.
> I didn't.
> 
> 
>> God DAMN me, for thinking you were one of the smart ones.
> 
> 
> At first I thought it was one of Rudy's forgeries.
> It isn't.
> 
> 
>> More reductio ad absurdum:
>>
>> Maybe Trump should have Air Force One park on the moon?
>>
>> Maybe the assassin could rent a rocket from Elon Musk and fly into orbit, if
>> he did, making your stupid fucking analogy moot.
>>
>> In outer space, there is no air resistance to slow down a bullet, so it would
>> travel much farther than it would on Earth. The distance a bullet travels in
>> space depends on its initial velocity and the lack of external forces acting
>> upon it.
>>
>> The muzzle velocity of a .30 caliber bullet can vary depending on the specific
>> cartridge and rifle used, but a typical muzzle velocity for a .30-06
>> Springfield rifle is around 2,700 feet per second (823 meters per second).
>>
>> In the vacuum of space, the bullet would maintain its initial velocity almost
>> indefinitely, as there is no air resistance to slow it down. However, it would
>> still be subject to the effects of gravity from nearby celestial bodies.
>>
>> Assuming the bullet is fired in a direction perpendicular to the Earth's
>> gravity, and neglecting the effects of gravity from other celestial bodies, we
>> can estimate the distance the bullet would travel.
>>
>> The kinetic energy of the bullet is given by KE=21mv2, where m is the mass of
>> the bullet and v is its velocity. For a .30-06 bullet, the mass is
>> approximately 0.18 kg (6.2 oz) and the velocity is 823 m/s.
>>
>> However, to estimate the distance traveled in space, we consider that the
>> bullet will travel in a straight line until it encounters another
>> gravitational field or an external force.
>>
>> Given that we do not know the direction of the bullet or the frame of
>> reference, let's assume it travels at a constant velocity of 823 m/s.
>>
>> The maximum distance the bullet could travel in a given time t would be d=v·t.
>>
>> Without a specified time, we can consider that in one year (approximately 3.15
>> ×107 seconds), the bullet would travel about d=823·3.15×107?2.59×1010 meters
>> or about 25.9 million kilometers.
>>
>> To put that in perspective, the Moon is about 384,400 kilometers away from
>> Earth, so the bullet could reach the Moon in about 468 seconds or
>> approximately 7.8 minutes.
>>
>> Keep in mind that this calculation assumes a constant velocity and neglects
>> any gravitational influences. In reality, the bullet's trajectory would be
>> influenced by the gravitational fields of nearby celestial bodies, causing its
>> path to curve over long distances.
> "
> 
> Thanks for the physics lesson Professor AlleyCat.
You mean where he gets it entirely wrong?