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If stupid has conveniently "forgotten" again, the scenario I presented was if 
someone shot at the moon from LEO.

This was stupid's scenario, which I shit on, because NO ONE thinks they can 
shoot the moon, unless they're playing Hearts.

"Particularly when the original question was a bullet fired from a rifle
down on terrestrial Earth." - -hh

Uhhh... no, it wasn't.

YOU were the one who introduced that stupid fucking shit into the conversation 
about "line of sight".

Typical fucked-in-the-head liberal nerd. Can't take the loss, so he changes 
the conditions of the argument.

If you want, I can post all of the thread and we can go over it point by 
point.

Naaaaah... 

PLONK!

=====

If an astronaut shot a .30-06 from low earth orbit, could the projectile reach 
the moon, not necessarily hitting the moon, just making it far enough?

The space craft is in low earth orbit, BETWEEN the Earth and moon. The 
projectile does NOT have to go through much of any atmosphere, if at all, or 
much of gravity, since the bullet will be traveling perpendicular to Earth.

In this case, the bullet is fired from a spacecraft in Low Earth Orbit (LEO), 
which is about 200-800 km above the Earth's surface, and it's traveling 
perpendicular to the Earth's gravity vector, directly towards the Moon.

Since the bullet is already in space, it doesn't have to overcome the Earth's 
atmosphere or a significant portion of the Earth's gravity well. The initial 
velocity of the bullet is about 2.5 km/s (muzzle velocity of the .30-06 
rifle), and it's added to the velocity of the spacecraft in LEO (about 7.8 
km/s).

The total initial velocity of the bullet is:

v0=2.5+7.8=10.3km/s

The distance from LEO to the Moon is about 384,400 km. To determine if the 
bullet can reach the Moon, we can use the equation for the trajectory of an 
object under constant velocity:

d=v0·t

where d is the distance traveled, v0 is the initial velocity, and t is the 
time.

We can also use the equation for the time it takes for an object to travel a 
certain distance at a constant velocity:

t=v0d

Substituting the values, we get:

t=10.3384,400?37,300seconds

There are 3600 seconds in an hour, so:

t?10.3hours

This means that the bullet can reach the Moon in approximately 10.3 hours.

So, to answer your question: yes, a .30-06 bullet fired from a spacecraft in 
LEO, perpendicular to the Earth's gravity vector, can reach the Moon in about 
10.3 hours.

Keep in mind that this calculation assumes a simplified model and neglects 
factors like the gravitational influence of the Earth and the Moon on the 
bullet's trajectory. In reality, the bullet's path will be more complex, and 
its actual time of flight may vary.

We'd have all the figuring of calculations ahead of time.

In that case, assuming you've done the calculations ahead of time and 
accounted for the various factors that affect the bullet's trajectory, such 
as:

Initial velocity: The combined velocity of the spacecraft and the bullet.

Direction: The precise direction of the bullet, taking into account the 
spacecraft's position and velocity.

Gravitational influences: The effects of the Earth's and Moon's gravity on the 
bullet's trajectory.

If you've accurately calculated the bullet's trajectory and accounted for 
these factors, it's likely the bullet CAN reach the Moon.

In fact, with precise calculations and accurate data, it's possible to hit the 
Moon with a bullet fired from a spacecraft in LEO. However, it's worth noting 
that:

Accuracy: The calculations would need to be extremely accurate to ensure the 
bullet hits the Moon.

Timing: The bullet's timing and trajectory would need to be precisely 
calculated to account for the Moon's motion and position.

Assuming you've done the calculations correctly, THE BULLET CAN INDEED REACH 
THE MOON.